amayajwilson88 amayajwilson88
  • 12-10-2022
  • Mathematics
contestada

h(t) =
h (0)
=
=
t-3
|
+6
t(t + 4)
t² +t+1,
te (-∞, -3)
, tɛ [−3, 3)
t≤ [3, ∞)

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