woodsc2896 woodsc2896

15-02-2024
Mathematics

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Find the integral of (1)/(√(16-x2))dx.
A) √(16-x2) + C
B) (1/2)√(16-x2) + C
C) (1/4)√(16-x2) + C
D) (1/8)√(16-x2) + C

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