jibjabsalar9378 jibjabsalar9378
  • 14-05-2018
  • Chemistry
contestada

A 0.12 m solution of a monoprotic acid is 2.3% ionized. what is the ka of this acid?

Respuesta :

PBCHEM
PBCHEM PBCHEM
  • 23-05-2018
Ionization of an acid of form (HA) can be represented as follows

HA   ↔     H+          +        A-

Ka = [tex] \frac{[H+][A-]}{[HA]} [/tex]

Now, initial conc. of HA = 0.12 M

Of these, 2.3 % got ionized.

∴ [H+] = [A-] = 0.12 X 0.023 = 0.00276 M

Thus [HA] left after ionization = 0.12 - 0.00276 = 0.11724 M

Now Ka =  [tex] \frac{(0.00276 )^2}{0.11724} [/tex]  = 6.497 x 10^-5
Answer Link

Otras preguntas

Which activity provides a low level of physical exercise? A. raking leaves B. walking the dog C. dancing D. washing dishes
For each item: classify organic or inorganic. 1. NaCl 2. phenol (C6H6O): . 3. C2H6: . 4. Ca3(PO4)2: . 5. formaldehyde (CH20): . 6. MgCO3: . 7. vitamin D2 (C27H4
Is yogurt capitalized
what is the answer of a - 5 + -12
What is a control group?
By common practice, scientists place scavengers at the same trophic level as which organism? Question 6 options: A. secondary consumers B. decomposers C. primar
How do demographers figure out population growth? A: by studying the level of the water supply B: by comparing birth and death rates C: by asking people how man
What is the product of 5/8 and 3/4??
what property does the number sentence for 8+0=8
what is the best example for biodiversity