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  • 11-07-2018
  • Mathematics
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help out please. :”)

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st4rgrl
st4rgrl st4rgrl
  • 11-07-2018
The answer is B. [tex] \frac{1}{3} [/tex].

Use PEMDAS to solve the exponents first, multiply/divide, etc.

[tex] \frac{5-8/2+6}{4+4*2+3^2} [/tex]
[tex] \frac{5-8/2+6}{4+4*2+9} [/tex]
[tex] \frac{5-4+6}{4+8*9} [/tex]
[tex] \frac{1+6}{4+17} [/tex]
[tex] \frac{7}{21} [/tex]

Divide both 7 and 21 by 7 to simplify to [tex] \frac{1}{3} [/tex].
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