Hey,here is the Answer to ur question.... Given: Angel BAC=BOA=90 degrees BO= 9 OC=7 AO=y To find: value of y Solution: In triangle BAC and triangle BOA ,we have, Angle BAC=angel AOB Angle B= Angle B (Angle B common in both triangles). =>triangle BAC similar to triangle BOA ( A.A criterion rule ) =>BA/BO=AC/OA=BC/BA =>BA/BO=BC/BA =>(BA)^2=BC*BO =>(BA)^2=16*9 =>(BA)^2=144 =>BA= root of 144 =>BA=12 So by Pythagoras theorem; (AB)^2=(BO)^2+(AO)^2 (12)^2=(9)^2+(y)^2 144=81+y^2 144-81=y^2 63=y^2 3root7=y Hope this helps you......
