vaish30 vaish30
  • 04-08-2018
  • Mathematics
contestada

make c the subject of p=c2/c2+4

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DeanR
DeanR DeanR
  • 04-08-2018

[tex] p= \dfrac{c^2}{c^2 + 4}[/tex]

[tex] c^2 p + 4 p = c^2 [/tex]

[tex] 4 p = c^2 - c^2 p = c^2(1-p)[/tex]

[tex]c^2 = \dfrac{4p}{1-p}[/tex]

[tex]c = \pm \sqrt{\dfrac{4p}{1-p} } = \pm 2 \sqrt{\dfrac{p}{1-p} } [/tex]

Answer: [tex]\quad c = \pm 2 \sqrt{\dfrac{p}{1-p} [/tex]

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