Respuesta :

[tex] \bf z=a+bi\\\\
-------------------------------\\\\
z+(4-2i)=-2+12i\implies z=-2-4+12i+2i
\\\\\\
z=-6+14i [/tex]

musiclover10045

Let the unknown number = X

Now we have X +(4-2i) = (-2+12i)

Subtract (4-2i) from both sides:

X = (−2+12i) - (4-2i)

X = -6+14i

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