3y-2z=7
y=[tex]\frac{2z+7}{3}[/tex]......equation(1)
Given x+2y-6=z
x=z-2y+6
putting value of y from equation(1)
By simplifying x=[tex]\frac{-z+4}{3}[/tex].....Equation(2)
Now putting the value of x and y in term of z in 3rd given equation
i.e 4+3x=2y-5z
i.e 2y-5z-3x=4
i.e 2([tex]\frac{2z+7}{3}[/tex])-5z-3([tex]\frac{-z+4}{3}[/tex])=4
By simplifying we will get -8z+14=24
i.e z=[tex]\frac{-5}{4}[/tex]
Now putting z value in Equation(1);y=3/4
And putting z value in Equation(2);x=7/3 (Answer)
