Respuesta :

jcherry99

Remark

This looks like an arithmetic series. If it is you should be able to show that the difference is a constant. It is shown like this

a_n - a_(n -1) = k

a2 - a1 = 10 - 2  = 8

a3 - a2 = 18 - 10 = 8

Conclusion It looks like we do have an arithmetic series.

100th number

a = 2

d = 8

n = 100

a_100 = ?

Formula

a_n = a + (n - 1)d

Solve

a_100 = 2 + (100 - 1) * 8

a_100 = 2 + 99*8

a_100 = 2 + 792

a_100 = 794  


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