sheb2347
sheb2347 sheb2347
  • 02-10-2018
  • Mathematics
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Help needed!! 10 points up! Please!!

Help needed 10 points up Please class=

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Аноним Аноним
  • 04-10-2018
[tex]<b>HEY MATE !![/tex]

Secx = [tex]\frac{25}{24}[/tex]

As we know secx = hypotenuse/ perpendicular

And cotx = Base / perpendicular

So now we have to find BASE .

[tex]{25}^{2}= {B}^{2}+ {24}^{2}[/tex]
625= [tex]{B}^{2}[/tex]+ 576
[tex]{B}^{2}[/tex] = 625 - 576
[tex]{B}^{2}[/tex] = 49

Taking squre root on both sides.

B = 7

Now cotx = 24/ 7

SO YOUR ANSWER IS OPTION . (C)

HOPE YOU LIKED.
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