y = [tex]\frac{3}{2}[/tex] x + 3
the equation of a line in slope-intercept form is
y = mx + c ( m is the slope and c the y-intercept )
calculate m using the gradient formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (0, 3) and (x₂, y₂ ) = (- 4, - 3)
m = [tex]\frac{-3-3}{-4-0}[/tex] = [tex]\frac{-6}{-4}[/tex] = [tex]\frac{3}{2}[/tex]
since the y-intercept is (0,3 ) then c = 3
y = [tex]\frac{3}{2}[/tex] x + 3 is the equation of the line
