aescalera15 aescalera15
  • 15-10-2018
  • Mathematics
contestada

find the equation of the line parallel to 2x-3y=9, passing through the point (-6,3)

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wegnerkolmp2741o
wegnerkolmp2741o wegnerkolmp2741o
  • 15-10-2018

parallel lines have the same slope so we need to find the slope of the line

2x-3y=9  get y alone

-3y=-2x+9  subtract 2x

y=2/3 x -3  divide by -3

the slope of the line is 2/3

the point slope form of the equation is

(y-y1) = m(x-x1) where m is  the slope and (x1.y1) is the point

y-3 = (2/3) * (x+6)   distribute the 2/3

y-3 = 2/3 x + 4  add 3 to both sides

y = 2/3 x +7

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