Answer:
[tex]\large\boxed{y=-35}[/tex]
Step-by-step explanation:
[tex]8+\dfrac{1}{5}y=1\qquad\text{subtract 8 from both sides}\\\\8-8+\dfrac{1}{5}y=1-8\\\\\dfrac{1}{5}y=-7\qquad\text{multiply both sides by 5}\\\\5\!\!\!\!\diagup^1\cdot\dfrac{1}{5\!\!\!\!\diagup_1}y=(5)(-7)\\\\y=-35[/tex]
