comfortsaliu comfortsaliu
  • 12-12-2018
  • Chemistry
contestada

Calculate the kinetic energy, in J/mole, of 1.00 mole of gaseous water molecules at room temperature (25.0ºC).

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kobenhavn kobenhavn
  • 21-12-2018

Answer: 23158.7J/mol

Explanation: Kinetic energy is the energy possessed by a body by virtue of its motion.

[tex]K.E=\frac{3}{2}\times {RT}[/tex]

R= gas constant= 8.314 J/Kmol

T= temperature in Kelvin = 25 ° C = 25° C+273= 298 K

[tex]K.E=\frac{3}{2}\times {8.314J/Kmol\times 298K}[/tex]

K.E = 23158.7 J

n= no of moles = 1 mole

Thu K.E per mole will be= 23158.7 J/mol




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