Step-by-step explanation:
[tex]\mathrm{If\:a\:function\:f\left(x\right)\:is\:mapping\:x\:to\:y,\:then\:the\:inverse\:functionof\:f\left(x\right)\:maps\:y\:back\:to\:x.}\\y=3x+5\\\mathrm{Interchange\:the\:variables}\:x\:\mathrm{and}\:y\\x=3y+5\\\mathrm{Solve}\:x=3y+5\:\mathrm{for}\:y\\\frac{x-5}{3}\\\frac{x-5}{3}[/tex]
[tex]f-^1(x)=\frac{5}{3} + \frac{x}{3}[/tex]
