abbieT5709 abbieT5709
  • 15-01-2019
  • Mathematics
contestada

Given that 1800k is a perfect cube, write the smallest possible value of k

Respuesta :

parmesanchilliwack parmesanchilliwack
  • 25-01-2019

Answer: 15

Step-by-step explanation:

A perfect cube is a whole number which is the cube of another whole number.

Since, the factor form of 1800 = [tex]2\times 2\times 2\times 3\times 3\times 5\times 5[/tex]

=  [tex]2^3\times 3^2\times 5^2[/tex]

Thus, we need to multiply 15 in the number 1800 for making it a perfect cube.

When we multiply 1800 by 15,

We get, 27000 which is a perfect square root.

Thus, the smallest value of k will be 15.

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