Respuesta :

kaleigh18

1) Determine mass of water driven off:

15.67 minus 7.58 = 8.09 g of water

2) Determine moles of MgCO3 and water:

MgCO3 ⇒ 7.58 g / 84.313 g/mol = 0.0899 mol 
H2O ⇒ 8.09 g / 18.015 g/mol = 0.449 mol

3) Find a whole number molar ratio:

MgCO3 ⇒ 0.0899 mol / 0.0899 mol = 1 
H2O ⇒ 0.449 mol / 0.0899 mol = 5MgCO3 · 5H2O

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