Answer:
Since b^2 -4ac = -31 we have 2 complex roots
Step-by-step explanation:
2x^2+ 5x+7=0
The discriminant is b^2 -4ac
when the equation is ax^2 +bx+c
so a =2 b=5 and c=7
(5)^2 - 4(2)(7)
25 - 56
-31
If b^2 -4ac > 0 we have 2 real distinct roots
If b^2 -4ac = 0 we have one real root
If b^2 -4ac < 0 we have two complex root
Since b^2 -4ac = -31 we have 2 complex roots
