Respuesta :

ckayep0cx2v

Answer:

(2, 8)

Step-by-step explanation:

A hole occurs when the denominator is equal to 0. In this case, the denominator equals zero when x = 2.

Next, we must find the value of y by factoring the numerator and simplifying:[tex]\frac{x^{2} +4x-12}{x-2} = \frac{(x-2)(x+6)}{x-2} = x+6[/tex]

Then plug in 2 for x:

2 + 6 = 8.

Therefore, there is a hole at (2, 8)

Otras preguntas