editsa
editsa editsa
  • 14-03-2019
  • Mathematics
contestada

Please help ASAP!
Use (f/g)x
f(x)=6x^2+36
g(x)=6x^2+34x-12
Show your work please!

Respuesta :

loumast
loumast loumast
  • 14-03-2019

Answer:

[tex]\frac{3}{3x-1}[/tex]

Step-by-step explanation:

[tex]\frac{f(x)}{g(x)}\\\frac{6x^2+36}{6x^2+34x-12}\\\frac{6(x^2+6)}{2(3x^2+17x-6)}[/tex]Factor out a 6 from the numerator and 2 from the denominator

[tex]\frac{3(x^2+6)}{3x^2+17x-6}[/tex] 2 in the denominator divides the 6 in the numerator

[tex]\frac{3(x+6)}{(3x-1)(x+6)}[/tex] factor the denominator, let me know if you need help with this

[tex]\frac{3}{3x-1}[/tex] the (x+6)s cancel

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