Answer:
[tex]\large\boxed{-\dfrac{5}{8}+\dfrac{1}{4}=-\dfrac{3}{8}}[/tex]
Step-by-step explanation:
[tex]-\dfrac{5}{8}+\dfrac{1}{4}=\dfrac{1}{4}+\left(-\dfrac{5}{8}\right)=\dfrac{1}{4}-\dfrac{5}{8}\\\\\text{find LCD:}\\\\8=2\cdot4,\ \text{therefore. LCD(4, 8) = 8}\\\\\dfrac{1}{4}=\dfrac{1\cdot2}{4\cdot2}=\dfrac{2}{8}\\\\\text{continuing}\\\\=\dfrac{2}{8}-\dfrac{5}{8}=\dfrac{2-5}{8}=-\dfrac{3}{8}[/tex]
