Answer:
[tex]\frac{15}{17}[/tex]
Step-by-step explanation:
Using the Pythagorean identity
sin²x + cos²x = 1, then
sin²x = 1 - cos²x
sinx = [tex]\sqrt{1-cos^2x}[/tex]
Hence
sinΘ = [tex]\sqrt{1-(8/17)^2}[/tex]
= [tex]\sqrt{1-\frac{64}{289} }[/tex]
= [tex]\sqrt{\frac{225}{289} }[/tex] = [tex]\frac{15}{17}[/tex]
