daveywright20 daveywright20
  • 13-05-2019
  • Mathematics
contestada

Does anyone know this?

Does anyone know this class=

Respuesta :

absor201
absor201 absor201
  • 13-05-2019

Answer:

h(1)= 1

h(4)=5

Step-by-step explanation:

Given

h(x)= x^3 for 1≤x≤3

and

h(x)=5 x>3

Now finding h(1), i.e when x=1

x=1 lies in the range 1≤x≤3 hence putting value x=1 in x^3

h(1)= 1^3

     = 1

Now finding h(4), i.e when x=4

x=1 lies in the range x<3 hence putting value x=4 in h(x)=5

h(4)= 5 !

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