For this case we must resolve the following expression:[tex]log_ {0.5} (16)[/tex]
We have to:
[tex]log_ {a} (x) = \frac {log_ {b} (x)} {log_ {b} (a)}[/tex]
The base change rule can be used if a and b are greater than 1 and are not equal to x.
We substitute the values in the base change formula, using [tex]b = 10[/tex]
[tex]\frac {log (16)} {log (0.5)} = - 4[/tex]
Answer:
-4
Option A
