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LammettHash

It's B.

If [tex]0<x<1[/tex], then it's also the case that [tex]0<x^2<1[/tex], because multiplying any number [tex]x[/tex] by a number (in this case, also [tex]x[/tex]) between 0 and 1 scales that number down.

It's not C, because [tex]2^2=4\neq3[/tex].

It's not D, because [tex]3^2=9\neq3[/tex].

piedpiperjk

Answer:

Point B

Step-by-step explanation:

The square root of 1 is one, so it must be larger than 1.

The square root of 2 is 4 so it must be smaller than 2.

B would make the most sense