Answer:
[tex](x-4)^2+(y-3)^2+(x-5)^2=6[/tex]
Step-by-step explanation:
The the center of the sphere is given as (a,b,c) and the radius is r, then the equation of the sphere would be:
[tex](x-a)^2+(y-b)^2+(x-c)^2=r^2[/tex]
From the info, we can say:
a = 4
b = 3
c = 5
r = [tex]\sqrt{6}[/tex]
Plugging into formula we get the equation:
[tex](x-a)^2+(y-b)^2+(x-c)^2=r^2\\(x-4)^2+(y-3)^2+(x-5)^2=(\sqrt{6} )^{2} \\(x-4)^2+(y-3)^2+(x-5)^2=6[/tex]
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