michaelcastaneda647 michaelcastaneda647
  • 04-07-2019
  • Mathematics
contestada

Sin2x=______


A.2sinxcosx

B.1/2(cos(a-b)-cos(a+b))

C.1-2sin^2x

D.2sinx+2cosx

Respuesta :

wegnerkolmp2741o
wegnerkolmp2741o wegnerkolmp2741o
  • 05-07-2019

Answer:

A.2sinxcosx

Step-by-step explanation:

We know the trig identity

Sin (2a) = 2 sin a cos a

sin (2x) = 2 sin x cos x

Answer Link
ambrown147
ambrown147 ambrown147
  • 12-06-2021

Answer:

2sinxcosx

Step-by-step explanation:

A P E X

Answer Link

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