Answer:
No one.
Step-by-step explanation:
[tex]\frac{(7^0)^3}{[tex]\\\frac{\frac{(7*3*2)^2}{(7*5)(7^0)^3}}{5^{-3} *5^ {-9}} = \frac{\frac{7^2*3^2*2^2}{(7*5)(1)}}{5^{-12}} =\frac{\frac{7*3^2*2^2}{5}}{5^{-12}} =\frac{7*3^2*2^2}{5^{-11}}= 7*3^2*2^2*{5^{11}}=1.23* 10^{10}[/tex]} = \frac{1}{5^ {-12}} = 5^ {12}[/tex]
