X^2 + 2x -4= 0
You need to remember one standard result
ax^2 + bx + c= 0
[tex]x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac} }{2a} [/tex]
By Comparing the coefficients,
a= 1, b=2, c=-4
[tex]x = \frac{ - 2 + - \sqrt{ {2}^{2} - 4 \times 1 \times - 4 } }{2 \times 1} \\ x = \frac{ - 2 + - \sqrt{4 + 16} }{2} \\ \\ x = \frac{ - 2 + - \sqrt{20} }{2} \\ \\ x = \frac{ - 2 + - 2 \sqrt{5} }{2} \\ \\ x = - 1 + - \sqrt{5} [/tex]
Options A ,C
