kaikeemmaashr
kaikeemmaashr kaikeemmaashr
  • 13-05-2016
  • Mathematics
contestada

Factor completely 10xy + 3y + 20ax + 6a.

(10x − 3)(y − 2a)

(10x − 3)(y + 2a)

(10x + 3)(y + 2a)

(10x + 3)(y − 2a)

Respuesta :

Aivi
Aivi Aivi
  • 18-05-2016
10 xy + 3y + 20 ax + 6a = y(10x+3) + a(20x+6) = y(10x+3)+2a(10x+6)= 
(y+2a)(10x+3)
Answer Link
DelcieRiveria DelcieRiveria
  • 10-05-2019

Answer:

Option 3 is correct.

Step-by-step explanation:

The given expression is

[tex]10xy+3y+20ax+6a[/tex]

This expression can be written as

[tex](10xy+3y)+(20ax+6a)[/tex]

Take out the common factors from each parenthesis.

[tex]y(10x+3)+2a(10x+3)[/tex]

Now, take out the common factor (10x+3).

[tex](10x+3)(y+2a)[/tex]

Therefore option 3 is correct.

Answer Link

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