Answer:
Final velocity v = 8.944 m/sec
Explanation:
We have given distance S = 40 meters
Time t = 10 sec
As it starts from rest so initial velocity u = 0
From second equation of motion [tex]s=ut+\frac{1}{2}at^2[/tex]
[tex]40=0\times 10+\frac{1}{2}a10^2[/tex]
[tex]a=0.8944m/sec^2[/tex]
Now from first equation of motion [tex]v=u+at[/tex], here v is final velocity, u is initial velocity, a is acceleration and t is time
So [tex]v=u+at=0+0.8944\times 10=8.944m/sec[/tex]
