Answer:
[tex]\large\boxed{y=-\dfrac{3}{2}x-10}[/tex]
Step-by-step explanation:
The slope-intercept form of an equation of a line:
[tex]y=mx+b[/tex]
m - slope
b - y-intercept
We have the point (-10, 5) and the slope m = -3/2.
Substitute to the equation of a line:
[tex]5=-\dfrac{3}{2}(-10)+b[/tex]
[tex]5=(3)(5)+b[/tex]
[tex]5=15+b[/tex] subtract 15 from both sides
[tex]5-15=15-15+b[/tex]
[tex]-10=b\to b=-10[/tex]
Finally we have:
[tex]\large{y=-\dfrac{3}{2}x-10}[/tex]
