yingling3 yingling3
  • 01-11-2019
  • Mathematics
contestada

how to solve this equation: ax² - 5x + 2 = 0

Respuesta :

calculista
calculista calculista
  • 04-11-2019

Answer:

[tex]x=\frac{5(+/-)\sqrt{25-8a}} {2a}[/tex]

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form

[tex]ax^{2} +bx+c=0[/tex]

is equal to

[tex]x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}[/tex]

in this problem we have

[tex]ax^{2} -5x+2=0[/tex]

so

[tex]a=a\\b=-5\\c=2[/tex]

substitute in the formula

[tex]x=\frac{5(+/-)\sqrt{-5^{2}-4(a)(2)}}{2a}[/tex]

[tex]x=\frac{5(+/-)\sqrt{25-8a}} {2a}[/tex]

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