thabomensonmannaesi2 thabomensonmannaesi2
  • 01-11-2019
  • Chemistry
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what is molarity of 10.5kg of NaSO4.10H2O IN 18.6OL OF SOLUTION

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vann18
vann18 vann18
  • 01-11-2019

Answer:

1.89 M is the molarity of the solution.

Explanation:

Assuming 10.5 kg of the hydrate, we need to calculate the amount of moles in the solution to be able to use the formula Molarity = mol / volume (in Liters).

So, the conversion would look like this:

10.5kg x (1000g/1kg) x (1 mol/299.22g) = 35.1 mol

Then, apply the formula M = mol/L

35.1 mol / 18.60 L = 1.89 M because the answer is 3 sig. figs. because of the "10.5" in the first conversion

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