BrownskinBoop9925 BrownskinBoop9925
  • 03-01-2020
  • Mathematics
contestada

Find the remainder when the polynomial $x^5 x^4 x^3 x^2 x$ is divided by $x^3-4x$.

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slicergiza slicergiza
  • 07-01-2020

Answer:

Remainder would be [tex]5x^2+21[/tex]

Step-by-step explanation:

Given,

Dividend = [tex]x^5+x^4+x^3+x^2+x[/tex]

Divisor = [tex]x^3-4x[/tex]

Using long division ( shown below ),

We get,

[tex]\frac{x^5+x^4+x^3+x^2+x}{x^3-4x}=x^2+x+5+\frac{5x^2+21}{x^3-4x}[/tex]

Therefore,

Remainder would be [tex]5x^2+21[/tex]

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