Answer:
Derivative of the function will be [tex]\frac{1}{x}[/tex]
Step-by-step explanation:
We have given expression [tex]y=ln\frac{x^2}{x}+1[/tex]
We have to differentiate this expression
[tex]y=ln\frac{x^2}{x}+1=lnx+1[/tex]
Now differentiating both side
[tex]\frac{dy}{dx}=\frac{1}{x}+0=\frac{1}{x}[/tex]
So value of derivative of the expression will be [tex]\frac{1}{x}[/tex]
