hkchambers01 hkchambers01
  • 12-02-2020
  • Mathematics
contestada

-200p^2+12028p=180096

Respuesta :

surjithayer10 surjithayer10
  • 12-02-2020

Answer:

Step-by-step explanation:

200 p²-12028p+180096=0

50 p-3007 p +45024=0

[tex]p=\frac{3007 \pm\sqrt{(-3007)^2-4*50*45024} }{2*50} \\=\frac{3007 \pm \sqrt{9042049-9004800} }{100} \\=\frac{3007 \pm \sqrt{37249} }{100} \\=\frac{ 3007 \pm193}{100} \\p=32,28.14[/tex]

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