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Water is boiled in a pan on a stove at sea level. During 10 min of boiling, it is observed that 200 g of water has evaporated. Determine the rate of heat transfer to the water. Solve this using appropriate software. Use data from the tables.

Respuesta :

Answer : The rate of heat transfer to the water is, 37.92 kJ/min

Explanation : Given,

Time = 10 min

Mass of water = 200 g

Latent heat of fusion of water = 334 J/g

Latent heat of vaporization of water = 2230 J/g

Now we have to calculate the rate of heat transfer to the water.

[tex]Q=\frac{m\times (L_v-L_f)}{t}[/tex]

Now put all the given values in the above formula, we get:

[tex]Q=\frac{200g\times (2230-334)J/g}{10min}[/tex]

[tex]Q=37920J/min=37.92kJ/min[/tex]

Thus, the rate of heat transfer to the water is, 37.92 kJ/min

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