Answer:
V=-26651.7V
Explanation:
The electric potential is for an electric charge is expressed as
V=kq/r.
Where K is constant, q is the charge and r is the distance.
Hence for a charge of +2.80 μC and - 6.20μC, both at distance 2.3m to each other, we can calculate the electric potential midway between them as
V=(kq/r)-(kq/r)
Since the mid way distance is 2.3/2=1.15m
Hence
V=K[(q/1.15) - (q/1.15)]
V=9*10⁹*10⁻⁶(2.43-5.39)
V=-26651.7V
