Answer: 133g/mol
Explanation:
To find the molar mass of Be(NO3)2, we must add the molar masses of all the individual elements present in the compound. This can be done by:
Molar Mass of Be(NO3)2 = 9 + 2[14 + (16x3)] = 9 + 2 [ 14 + 48]
= 9 + 2[62] = 9 + 124 = 133g/mol
