gonzalezbarbara711 gonzalezbarbara711
  • 14-03-2020
  • Mathematics
contestada

find the VERTEX of the parabola f(x) = x^2 - 16x + 63

Respuesta :

jimrgrant1 jimrgrant1
  • 14-03-2020

Answer:

vertex = (8, - 1 )

Step-by-step explanation:

Given a parabola in standard form, f(x) = ax² + bx + c : a ≠ 0

Then the x- coordinate of the vertex is

[tex]x_{vertex}[/tex] = - [tex]\frac{b}{2a}[/tex]

f(x) = x² - 16x + 63 ← is in standard form

with a = 1 and b = - 16, thus

[tex]x_{vertex}[/tex] = - [tex]\frac{-16}{2}[/tex] = 8

Substitute x = 8 into f(x)

f(8) = 8² - 16(8) + 63 = 64 - 128 + 63 = - 1

vertex = (8, - 1 )

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