Answer:
[tex](x+8y^2-3)(x-8y^2-3)[/tex]
Step-by-step explanation:
[tex](x-3)^2-(8y^2)^2\\\left(\left(x-3\right)+8y^2\right)\left(\left(x-3\right)-8y^2\right)[/tex]
All you do above is rewrite it and then and apply differences of squares formula. After that, all you have to do is just refine it.
So therefore, your answer is [tex](x+8y^2-3)(x-8y^2-3)[/tex]
