lisbetsanchez57 lisbetsanchez57
  • 15-04-2020
  • Mathematics
contestada

onsider the equation 0.5 times e4z =13 solve the equation for z. express the solution as a logarithm in base e

Respuesta :

mberisso
mberisso mberisso
  • 15-04-2020

Answer:

[tex]z=\frac{ln(26)}{4}[/tex]

Step-by-step explanation:

The given equation is:

[tex]0.5\,e^{4z}=13[/tex]

so, we first isolate the exponential form that contains the unknown "z" in the exponent, by dividing both sides by 0.5:

[tex]0.5\,e^{4z}=13\\e^{4z}=\frac{13}{0.5}\\e^{4z}=26[/tex]

Now we bring the exponent down by applying the natural log function on both sides, and then solve for "z":

[tex]e^{4z}=26\\ln(e^{4z})=ln(26)\\4\,z=ln(26)\\z=\frac{ln(26)}{4}[/tex]

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