akirasamuals7
akirasamuals7 akirasamuals7
  • 01-05-2020
  • Mathematics
contestada

Solve logx = -3 by changing it to exponential form.
A.x=1/10^3
B.x=-30
C.x=30
D.x=1/3^10

Respuesta :

jimrgrant1 jimrgrant1
  • 01-05-2020

Answer:

A

Step-by-step explanation:

Using the rule of logarithms

[tex]log_{b}[/tex] x = n ⇒ x = [tex]b^{n}[/tex]

Given

[tex]log_{10}[/tex] x = - 3, then

x = [tex]10^{-3}[/tex] = [tex]\frac{1}{10^{3} }[/tex] → A

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