shiaSandJennnocle
shiaSandJennnocle shiaSandJennnocle
  • 15-08-2016
  • Mathematics
contestada

Simplify (1+csc x)/cos x+cot x

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princegn
princegn princegn
  • 15-08-2016
(1 + cscx)/cosx+cotx = (1+cscx)/(cosx+cosx/sinx)
 = (1+cscx)/cosx(1+1/sinx)
 = (1+cscx)/cosx(1+cscx)
 = 1/cosx
 = secx
Answer Link
Hussain514 Hussain514
  • 18-08-2016
(1+cscx)/(cos x + cot x) 
As cosec x is the inverse of sinx 
csc x = 1/sinx,
and cotx is the ratio of cosx and sinx 
cotx = cosx/sinx
(1+cscx)/(cos x + cot x) 
(1 + 1/sinx) / (cosx + cosx/sinx)
BY taking LCM:
(sinx +1) / sinx* [ (sinxcosx + cosx) / sinx]
 (sinx + 1) / (sinxcosx + cosx)
Taking cosx as common: 

= (sinx + 1) / cosx*(sinx + 1) 
= 1/ cosx is the answer
Answer Link

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