Respuesta :
Answer:
P(x < 92) is 0.16
Step-by-step explanation:
We are given that the normal distribution has a mean of 98 and a standard deviation of 6.
Mean =[tex]\mu = 98[/tex]
Standard deviation = [tex]\sigma = 6[/tex]
We are supposed to find P(x < 92)
Formula : [tex]Z=\frac{x-\mu}{\sigma}[/tex]
[tex]Z=\frac{92-98}{6}[/tex]
Z=-1
Refer the z table for p value
So,p value = 0.1587
So, P(x < 92) is 0.16
Option A is true
Hence P(x < 92) is 0.16
