tookoolforschool30 tookoolforschool30
  • 11-05-2020
  • Mathematics
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Find the 35th term of the sequence given: (3, 14, 25,...)
Find the 35th term of the sequence given: (3, 14, 25, ...)

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altavistard
altavistard altavistard
  • 12-05-2020

Answer:

377 = a(35)

Step-by-step explanation:

This is an arithmetic sequence with first term 3 and common differernce 11.  Notice how each new term is equal to the previous term, plus 11.

So we have a(n) = 3 + 11(n - 1), and here that becomes

a(35) = 3 + 11(35 - 1) = 3 + 11(34) = 3 + 374 = 377 = a(35)

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