Norielle3k
Norielle3k Norielle3k
  • 14-05-2020
  • Mathematics
contestada

x^2+y^2- 2y - 99 = 0
What is the center of this circle ? What is the radius of this circle

Respuesta :

altavistard
altavistard altavistard
  • 16-05-2020

Answer:

Center:  (0, 1); radius:  10

Step-by-step explanation:

Your x^2+y^2- 2y - 99 = 0 is centered at (0, k):

(x - 0)^2 + y^2 - 2y - 99 = 0

and you must "complete the square" of y^2- 2y

to determine the value of k:

(x - 0)^2 + y^2 - 2y + 1 - 1 - 99 = 0, or

(x - 0)^2 + (y - 1)^2 = 100 = 10^2

The center is at (h, k) :  (0, -1) and the radius is 10.

The equation in final form is

x^2 + (y - 1)^2 = 10^2

The radius is 10.  That is, since r^2 = 100, r must be 10.

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