linniemouse linniemouse
  • 14-05-2020
  • Chemistry
contestada

How many moles of potassium nitrate are required to make 550 mL of a 2.1M solution?

Respuesta :

onyebuchinnaji
onyebuchinnaji onyebuchinnaji
  • 19-05-2020

Answer:

1.155 moles

Explanation:

Given;

volume of solution, V =  550 mL

solution molality, M =  2.1M

Molality = number of moles of solute / litre of solvent

number of moles of solute (potassium nitrate ) = molality x litre of solvent

number of moles of solute (potassium nitrate ) = 2.1 x 550 x 10⁻³

number of moles of solute (potassium nitrate ) = 1.155 moles

Therefore, there are 1.155 moles of potassium nitrate  in the solution.

Answer Link
Raineyvonahnen
Raineyvonahnen Raineyvonahnen
  • 29-05-2021

Answer:

B. 1.2

Explanation:

Answer Link

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