sanchez39929
sanchez39929 sanchez39929
  • 04-06-2020
  • Mathematics
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Can someone help :(!

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Respuesta :

sqdancefan
sqdancefan sqdancefan
  • 04-06-2020

Answer:

  1/(t+4)²

Step-by-step explanation:

  [tex]\dfrac{t+3}{t+4}\div(t^2+7t+12)=\dfrac{t+3}{t+4}\cdot\dfrac{1}{(t+3)(t+4)}=\dfrac{(t+3)}{(t+3)(t+4)^2}\\\\=\boxed{\dfrac{1}{(t+4)^2}}[/tex]

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